Bug 25137 - SortedSubSet::Reverse() always returns an empty set.
Summary: SortedSubSet::Reverse() always returns an empty set.
Status: RESOLVED FIXED
Alias: None
Product: Class Libraries
Classification: Mono
Component: System ()
Version: master
Hardware: PC Linux
: --- normal
Target Milestone: Untriaged
Assignee: Marek Safar
URL:
Depends on:
Blocks:
 
Reported: 2014-12-07 11:37 UTC by luk32
Modified: 2014-12-08 06:04 UTC (History)
3 users (show)

Tags:
Is this bug a regression?: ---
Last known good build:


Attachments
Sample program. subSet has count of 3. subSet.Reverse().Count() returns 0. (560 bytes, text/x-csharp)
2014-12-07 11:37 UTC, luk32
Details


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Status:
RESOLVED FIXED

Description luk32 2014-12-07 11:37:15 UTC
Created attachment 8990 [details]
Sample program. subSet has count of 3. subSet.Reverse().Count() returns 0.

`SortedSubSet::Reverse()` called on a non-empty Sorted created via `SortedSet::GetViewBetween()` returns an IEnumerable over an empty set.

I think this is a bug due to implementation of `SortedSubSet/SortedSet::Reverse()`, because the loop in the implementation of `Reverse` is based on `tree.Count`.

I am not sure where this value is taken from for a call made from SortedSubSet, whether it's the host's tree or not intialized at all. Though, I couldn't find any place where the `GetItem` would get information that the call is being made for the view of a tree, not the full one.

I attached a simple program depicting the issue.
Comment 1 Marek Safar 2014-12-08 06:04:52 UTC
Fixed in master